60=2x^2-22x

Solution for 60=2x^2-22x equation:

60=2x^2-22x

We move all terms to the left:

60-(2x^2-22x)=0

We get rid of parentheses

-2x^2+22x+60=0

a = -2; b = 22; c = +60;
Δ = b2-4ac
Δ = 222-4·(-2)·60
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{241}}{2*-2}=\frac{-22-2\sqrt{241}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{241}}{2*-2}=\frac{-22+2\sqrt{241}}{-4}
$